View Full Version : November Entry: Map Vandal

Map Vandal

11-04-2008, 03:53 PM

This sounds like it will be a lot of fun. I have never drawn anything for a science fiction setting before so I think I will throw my hat in the ring. Here is something I started this morning. I am not exactly sure where I might go with this, but any suggestions would be welcome.

### Latest WIP ###

Steel General

11-04-2008, 04:51 PM

Nice start, looking forward to seeing more.

Ascension

11-04-2008, 05:46 PM

The numbers throw me off as I don't even know what they refer to...I'm sure it's something but I'm also sure that it's way over my head :) Might make that text smaller so it isn't so overwhelming. The red planet has 2 moons on the same orbital path (the vertical one). Looks pretty good though so my nits don't really need picking :)

ravells

11-04-2008, 06:05 PM

That's a very nifty start , Map Vandal. Nice clean feel to it, and I love the equations. the starfield background is glorious too. I just feel that it needs something more to complete it (but I don't know what it is) - a funky border maybe? Is the story behind the picture the prediction of some sort of meteor or asteroid collision?

nolgroth

11-10-2008, 02:06 PM

I like the bold, vivid color on this map. I wish I had half the math skills to figure out all the equations. ;)

Bedwyr

11-20-2008, 12:50 PM

Let me take some guesses on the equations (I haven't taken any orbital mechanics class or physics beyond regular old kinematics stuff yet).

m is a mass ratio of some kind. Stellar Mass unit?

Below are what look to be standard x,y,z coordinates.

Ve I guess is the velocity of the earth.

So your change (delta) velocity (V) is Ve times the natural log of a ratio of masses.

So you get delta-V expressed against your Ve. e^delta-V/Ve for some reason. the minus 1 is probably derived from some difference equation with some calculus fun in there. Capital E is always total energy and that's a very familiar equation: E = 1/2mv^2 or mass times velocity squared. It's just that you've got this strange coefficient inside.

The topmost equation is a derivative of some kind expressed as relative to mass? (dm/m)

Lower right, the summation of forces equals delta P (potential energy?) divided by delta t (time), taking the limit as t approaches 0. So some kind of instantaneous force summation defined by P.

How close am I so far?

mmmmmpig

11-20-2008, 01:30 PM

Niiice entry. I think the path you have shown could stand out more if you removed every other triangle from the line. There is a bit of visual clutter that distracts the eye somewhat. Don't be afraid to use extremely small text. The "m=" text could be significantly smaller and would not negatively impact the map in the least.

Good stuff

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