Conversation Between Feralspirit and Korash

4 Visitor Messages

1. I did the same as you

....... The basic math of an equilateral 90 degree triangle is that the sides of a right angle with the opposite angels of 45 will be equal. => a 6 foot wall at 9 (or 3) o'clock will cast a 6 foot shadow. The length of the shadow will always follow the same basic math principles of a right angle depending on the angle of the sun.

Using your logic you have 80 foot trees which are HUGE. No prob if that is what you want.

Good work all the same.
2. You did what I thought you did for the shadows selecting building and applying shadow according to the hieght. I hadn't thought about doing that until I saw your map, and was wondering if I got it right. Nice tip that.

About your assumption on shadow lenth, I believe you have it off a bit. Assume that the sun is up 12 hours a day, and high noon the sun is directly overhead and rises and sets 6 hours before and after. I know that is not the true case, but....

Given that assumption, the shadows are longest just after the sun rises, and before it sets. At noon the only shadows are those under overhead cover, and for our purposes, non-existent. Half way through its upward or downward arc (9 & 3 respectfully) is when it would be at 45 degrees. Any object at that time will cast a shadow of a length equal to its height.......