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Thread: cylindrical equal-area projection

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  1. #4

    Question

    I have looked into it and i get out the following:

    If i want to make a projection i will need for each (x,y) an altitude. I can find the altitude in a (lon,lat) form. So to get the altitude of (x,y) i will need to know the (lon,lat) of (x,y).

    (x,y)=(lon,lat)

    x = 2*pi*cos(theta) * (lon + 180)/360
    lon = (x*360)/(2*pi*cos(theta))-180

    y = R*sin(lat)/cos(phi)
    lat=invsin(cos(phi)*y/R)

    so (x,y)=(lon,lat)=( (x*360)/(2*pi*cos(theta))-180, invsin(cos(phi)*y/R)) )

    so i should be able to calculate the altitude of (x,y) by taking the altitude of ( (x*360)/(2*pi*cos(theta))-180, invsin(cos(phi)*y/R)) ).

    is this correct? And what is phi? Is it the standard latitude, and what number should i enter?
    Last edited by haroim; 03-21-2009 at 04:02 AM. Reason: invsin(cos(phi*y/R)) must be invsin(cos(phi)*y/R))

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