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Thread: Distances of Interest

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  1. #10

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    r = radius of Mars in feet
    C1 = circumference of Mars in feet
    C2 = new length of rope in feet
    pi = 3.14159
    L = additional length of rope necessary.

    C1 = 2 * pi * r
    C2 = 2 * pi * ( r + 6 )

    C2 - C1 = L

    Equatorial radius of Mars = 3396.2 km = 11142388 feet

    C1 = 70009629 feet
    C2 = 70009667 feet

    L = 38 feet.

    That doesn't seem long enough. Maybe I'll recheck my math...

    edit: No, I'm right. C + x = ( 2 * pi * r ) + ( 2 * pi * ( r + x ) ) That's kind of strange; you'd think it would be much bigger.
    Last edited by Midgardsormr; 04-28-2008 at 11:49 AM.
    Bryan Ray, visual effects artist
    http://www.bryanray.name

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